4x^2=342

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Solution for 4x^2=342 equation:



4x^2=342
We move all terms to the left:
4x^2-(342)=0
a = 4; b = 0; c = -342;
Δ = b2-4ac
Δ = 02-4·4·(-342)
Δ = 5472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5472}=\sqrt{144*38}=\sqrt{144}*\sqrt{38}=12\sqrt{38}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{38}}{2*4}=\frac{0-12\sqrt{38}}{8} =-\frac{12\sqrt{38}}{8} =-\frac{3\sqrt{38}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{38}}{2*4}=\frac{0+12\sqrt{38}}{8} =\frac{12\sqrt{38}}{8} =\frac{3\sqrt{38}}{2} $

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